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36v^2+24v=0
a = 36; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·36·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*36}=\frac{-48}{72} =-2/3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*36}=\frac{0}{72} =0 $
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